Lesson 4: The Midpoint Formula
Learning Objectives
By the end of this lesson, students will be able to:
- Apply the midpoint formula to find the center point of a line segment
- Understand midpoint as the average of coordinates
- Use midpoints to solve geometric problems
- Find unknown endpoints when given a midpoint
- Apply midpoint concepts to real-world situations
Introduction
The midpoint of a line segment is the point that divides it into two equal parts - exactly halfway between the two endpoints. This concept is crucial in many applications: finding the center of a bridge, determining meeting points, locating optimal facility placements, and solving geometric problems.
The Midpoint Formula
For a line segment with endpoints \((x_1, y_1)\) and \((x_2, y_2)\), the midpoint M is:
\[ M = \left(\frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2}\right) \]
Understanding the Formula
The midpoint formula simply takes the average of the x-coordinates and the average of the y-coordinates: - Midpoint x-coordinate: \(\frac{x_1 + x_2}{2}\) - Midpoint y-coordinate: \(\frac{y_1 + y_2}{2}\)
Think of it as finding the “balance point” between two locations.
Basic Examples
Example 1: Simple Midpoint Calculation
Find the midpoint of the line segment joining A(2, 3) and B(8, 7).
Solution: \[ M = \left(\frac{2 + 8}{2}, \frac{3 + 7}{2}\right) \] \[ M = \left(\frac{10}{2}, \frac{10}{2}\right) \] \[ M = (5, 5) \]
The midpoint is at (5, 5).
Example 2: Midpoint with Negative Coordinates
Find the midpoint of the line segment joining P(-4, 6) and Q(2, -2).
Solution: \[ M = \left(\frac{-4 + 2}{2}, \frac{6 + (-2)}{2}\right) \] \[ M = \left(\frac{-2}{2}, \frac{4}{2}\right) \] \[ M = (-1, 2) \]
Example 3: Midpoint with the Origin
Find the midpoint of the line segment joining O(0, 0) and R(10, 6).
Solution: \[M = \left(\frac{0 + 10}{2}, \frac{0 + 6}{2}\right)\] \[M = (5, 3)\]
Note: The midpoint between the origin and any point \((a, b)\) is \(\left(\frac{a}{2}, \frac{b}{2}\right)\).
Example 4: Midpoint with Fractional Coordinates
Find the midpoint of S(1.5, 2.5) and T(4.5, 6.5).
Solution: \[M = \left(\frac{1.5 + 4.5}{2}, \frac{2.5 + 6.5}{2}\right)\] \[M = \left(\frac{6}{2}, \frac{9}{2}\right)\] \[M = (3, 4.5)\]
Real-World Applications
Example 5: Meeting Point
Two friends live at coordinates A(2, 8) and B(10, 4). They want to meet exactly halfway between their houses. Where should they meet?
Solution: \[M = \left(\frac{2 + 10}{2}, \frac{8 + 4}{2}\right) = (6, 6)\]
They should meet at location (6, 6).
Example 6: Facility Placement
A straight road connects town A at coordinates (10, 20) to town B at coordinates (50, 60). The council wants to place a rest stop at the midpoint. What are the coordinates?
Solution: \[M = \left(\frac{10 + 50}{2}, \frac{20 + 60}{2}\right) = (30, 40)\]
The rest stop should be built at (30, 40).
Example 7: Bridge Center Point
A bridge spans across a river from point P(-12, 5) to point Q(8, 15). Engineers need to place a support at the center of the bridge. What are its coordinates?
Solution: \[M = \left(\frac{-12 + 8}{2}, \frac{5 + 15}{2}\right)\] \[M = \left(\frac{-4}{2}, \frac{20}{2}\right)\] \[M = (-2, 10)\]
The support should be at (-2, 10).
Example 8: Emergency Services
An ambulance station needs to be equidistant from two hospitals: - Hospital A: (5, 12) - Hospital B: (15, 8)
Where should the station be located to be exactly halfway between them?
Solution: \[M = \left(\frac{5 + 15}{2}, \frac{12 + 8}{2}\right) = (10, 10)\]
The station should be at (10, 10).
Working Backwards: Finding Unknown Endpoints
Sometimes we know the midpoint and one endpoint, and need to find the other endpoint.
Example 9: Finding the Other Endpoint
The midpoint of segment AB is M(5, 7). If point A is at (2, 3), find the coordinates of point B.
Solution:
Let B = \((x, y)\)
Using the midpoint formula: \[\frac{2 + x}{2} = 5 \text{ and } \frac{3 + y}{2} = 7\]
Solve for x: \[2 + x = 10\] \[x = 8\]
Solve for y: \[3 + y = 14\] \[y = 11\]
Therefore, B = (8, 11)
Check: Midpoint of (2, 3) and (8, 11) = \(\left(\frac{2+8}{2}, \frac{3+11}{2}\right) = (5, 7)\) ✓
Example 10: Finding the Starting Point
A delivery driver ends their route at point E(20, 30). The midpoint of their route was at M(12, 18). Where did they start?
Solution:
Let the starting point be S\((x, y)\)
\[\frac{x + 20}{2} = 12 \text{ and } \frac{y + 30}{2} = 18\]
Solve for x: \[x + 20 = 24\] \[x = 4\]
Solve for y: \[y + 30 = 36\] \[y = 6\]
The driver started at (4, 6).
Example 11: Symmetric Point
Point P(3, 5) is given. Find the point Q that is symmetric to P with respect to the origin (0, 0).
Solution:
If the origin is the midpoint between P and Q, then:
Let Q = \((x, y)\)
\[\frac{3 + x}{2} = 0 \text{ and } \frac{5 + y}{2} = 0\]
\[x = -3 \text{ and } y = -5\]
Point Q is at (-3, -5).
This is reflection through the origin.
Multiple Midpoints
Example 12: Trisecting a Line Segment
Points A(0, 0) and B(9, 6) are the endpoints of a segment. Find two points that divide the segment into three equal parts.
Solution:
First, find the midpoint M of AB: \[M = \left(\frac{0+9}{2}, \frac{0+6}{2}\right) = (4.5, 3)\]
Now find the midpoint of AM: \[P = \left(\frac{0+4.5}{2}, \frac{0+3}{2}\right) = (2.25, 1.5)\]
And the midpoint of MB: \[Q = \left(\frac{4.5+9}{2}, \frac{3+6}{2}\right) = (6.75, 4.5)\]
However, this doesn’t trisect. To trisect, we need: - First point at 1/3 of the way: \((x_1 + \frac{1}{3}(x_2-x_1), y_1 + \frac{1}{3}(y_2-y_1)) = (3, 2)\) - Second point at 2/3 of the way: \((x_1 + \frac{2}{3}(x_2-x_1), y_1 + \frac{2}{3}(y_2-y_1)) = (6, 4)\)
The two trisection points are (3, 2) and (6, 4).
Example 13: Median of a Triangle
A triangle has vertices at A(0, 0), B(6, 0), and C(3, 6). Find the median from vertex A to side BC.
Solution:
Step 1: Find the midpoint M of BC: \[M = \left(\frac{6+3}{2}, \frac{0+6}{2}\right) = (4.5, 3)\]
Step 2: The median is the line segment from A(0, 0) to M(4.5, 3).
The median from A has endpoint at (4.5, 3).
Geometric Properties Using Midpoints
Example 14: Proving a Parallelogram
Show that quadrilateral ABCD with vertices A(1, 2), B(5, 3), C(6, 6), and D(2, 5) is a parallelogram by showing that the diagonals bisect each other.
Solution:
Find the midpoint of diagonal AC: \[M_{AC} = \left(\frac{1+6}{2}, \frac{2+6}{2}\right) = (3.5, 4)\]
Find the midpoint of diagonal BD: \[M_{BD} = \left(\frac{5+2}{2}, \frac{3+5}{2}\right) = (3.5, 4)\]
Since both diagonals have the same midpoint, they bisect each other, proving ABCD is a parallelogram.
Example 15: Finding the Center of a Circle
Three points on a circle are A(0, 4), B(4, 0), and C(0, -4). The center lies on the perpendicular bisector of any chord. Find an approximation of the center.
Solution:
Find midpoint of AB: \[M_{AB} = \left(\frac{0+4}{2}, \frac{4+0}{2}\right) = (2, 2)\]
The center is somewhere on the perpendicular bisector through (2, 2).
Find midpoint of AC: \[M_{AC} = \left(\frac{0+0}{2}, \frac{4+(-4)}{2}\right) = (0, 0)\]
This suggests the center might be near the origin. By symmetry with points A and C, the center is at (0, 0) and the radius is 4.
Connection to Other Lessons
Link to Distance Formula (Lesson 3)
The two endpoints are equidistant from the midpoint:
Example 16: Verify that M(4, 5) is equidistant from A(1, 2) and B(7, 8).
Distance from M to A: \[d_{MA} = \sqrt{(4-1)^2 + (5-2)^2} = \sqrt{9+9} = \sqrt{18} = 3\sqrt{2}\]
Distance from M to B: \[d_{MB} = \sqrt{(7-4)^2 + (8-5)^2} = \sqrt{9+9} = \sqrt{18} = 3\sqrt{2}\]
Both distances equal \(3\sqrt{2}\), confirming M is the midpoint.
Link to Maps (Lesson 2)
Example 17: On a map with scale 1:10,000, two landmarks are at (240, 180) and (360, 260). Each unit represents 10 meters. Where should a information sign be placed at the midpoint?
Solution: \[M = \left(\frac{240+360}{2}, \frac{180+260}{2}\right) = (300, 220)\]
The sign should be at grid position (300, 220).
Practice Exercises
Worksheet 1C: Midpoint Practice
- Find the midpoint of the line segment from (2, 8) to (10, 4).
- Find the midpoint of the line segment from (-3, 7) to (5, -1).
Set 1: Basic Midpoint Calculations
- Find the midpoint of the line segment joining:
- A(4, 6) and B(10, 12)
- C(-2, 5) and D(6, -3)
- E(0, 8) and F(8, 0)
- G(-5, -7) and H(-1, -3)
- Find the midpoint between:
- The origin and (12, 16)
- (3.5, 7.2) and (8.5, 4.8)
- \((-\frac{1}{2}, 3)\) and \((\frac{5}{2}, 7)\)
Set 2: Finding Unknown Endpoints
The midpoint of segment PQ is M(6, 4). If P is at (2, 1), find Q.
The midpoint of segment RS is M(-3, 5). If S is at (1, 9), find R.
Point A(5, 8) is one endpoint. The midpoint is M(3, 4). Find the other endpoint B.
A segment has midpoint (0, 0) and one endpoint at (7, -3). Find the other endpoint.
Set 3: Applications
Two warehouses are located at A(12, 18) and B(28, 34). A distribution center will be built exactly halfway between them. What are its coordinates?
A park bench should be placed at the midpoint between two trees at positions T₁(-8, 6) and T₂(4, 14). Where should the bench go?
On a map, a school is at (15, 20) and a library is at (35, 40). Where should a crosswalk be placed on a straight path connecting them, exactly at the midpoint?
Set 4: Geometric Applications
A rectangle has opposite vertices at (2, 3) and (10, 11). Find the coordinates of the center of the rectangle.
Triangle ABC has vertices A(0, 0), B(8, 0), and C(4, 6). Find:
- The midpoint of side AB
- The midpoint of side BC
- The midpoint of side AC
Show that the quadrilateral with vertices P(1, 1), Q(5, 2), R(6, 6), and S(2, 5) is a parallelogram by proving the diagonals bisect each other.
Set 5: Challenge Problems
Points A, B, and C are collinear (on the same line) with B between A and C. If A is at (2, 3), B is at (5, 7), and B is the midpoint of AC, find C.
The midpoint of XY is M(4, 6) and the midpoint of YZ is N(7, 9). If X is at (1, 3), find Z.
Three vertices of a parallelogram are A(1, 2), B(5, 4), and C(7, 7). Find all possible locations for the fourth vertex D. (Hint: There are three possible parallelograms)
A segment AB is divided into four equal parts by points P, Q, and R (in that order). If A is at (0, 0) and B is at (12, 8), find the coordinates of P, Q, and R.
Real-World Applications
Urban Planning
City planners use midpoints to: - Determine optimal locations for public facilities - Place street lights evenly along roads - Design bus stops at convenient intervals
Sports
- Finding the center circle of a sports field
- Placing mid-court lines in basketball
- Determining fair meeting points for tournaments
Engineering
- Locating support beams at the center of bridges
- Finding balance points in structural design
- Calculating center of mass for symmetric objects
Additional Resources
Interactive Tools
- Desmos: Plot segments and automatically show midpoints
- GeoGebra: Explore midpoint properties dynamically
- Online midpoint calculators for checking work
Extension Topics
- Weighted Midpoints: When one endpoint is “heavier” than the other
- Centroids: The “average” point of a triangle (uses midpoints)
- Perpendicular Bisectors: Lines through midpoints perpendicular to segments
Key Formulas Summary
Midpoint Formula: \[M = \left(\frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2}\right)\]
Finding Other Endpoint: If M\((m_x, m_y)\) is the midpoint of AB and A\((x_1, y_1)\) is known: \[B = (2m_x - x_1, 2m_y - y_1)\]
Verification: Distance from A to M equals distance from M to B.
Homework
Complete Practice Exercises Sets 1 and 2, and at least 3 problems from Set 3.
For additional worksheets and practice problems, visit the Resources section.
- (6, 6)
- (1, 3)
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