Lesson 10: Equation of a Line from Gradient and a Point
Learning Objectives
By the end of this lesson, students will be able to:
- Use point-slope form to write an equation from a gradient and a point
- Convert equations to slope-intercept form
- Check whether a point lies on a line
Point-Slope Form
If a line has gradient \(m\) and passes through \((x_1, y_1)\), then:
\[y - y_1 = m(x - x_1)\]
Example 1: Write an Equation from a Gradient and a Point
Find the equation of the line with gradient 4 passing through (2, -1).
Solution: \[y - (-1) = 4(x - 2)\] \[y + 1 = 4x - 8\] \[y = 4x - 9\]
Example 2: Keep in Point-Slope Form
Find the equation of the line with gradient \(-\frac{3}{2}\) passing through (6, 5).
Solution: \[y - 5 = -\frac{3}{2}(x - 6)\]
Example 3: Check a Point
Does (3, 7) lie on the line \(y = 2x + 1\)?
Solution: \[2(3) + 1 = 7\] Yes, the point lies on the line.
Practice Exercises
- Write the equation of the line with gradient 3 passing through (-1, 4).
- Write the equation of the line with gradient \(-2\) passing through (5, 9).
- Convert your equations from (1) and (2) to slope-intercept form.
- Determine whether (4, -3) lies on the line \(y = -x + 1\).
Worksheet 2C: Gradient and a Point
- Write the equation of the line:
- With gradient 2 passing through (1, -3)
- With gradient \(-\frac{1}{2}\) passing through (6, 4)
- Convert to slope-intercept form:
- \(y - 7 = 5(x + 1)\)
- \(y + 2 = -3(x - 4)\)
- Check whether each point lies on the line \(y = 3x - 2\):
- (1, 1)
- (2, 4)
NoteWorksheet 2C Answers
- \(y = 2x - 5\), \(y = -\frac{1}{2}x + 7\)
- \(y = 5x + 12\), \(y = -3x + 10\)
- Yes, yes
Previous Lesson: Lesson 9: Perpendicular Lines
Next Lesson: Lesson 11: Practice and Revision